Question

prove it ... Parallelogram on the same base and having equal areas lie between the same parallels

Answer 1

$\textsf{Let ABCD and ABEF be parallelograms}$

$\textsf{lying on the same base and betweeen the same parallels}$

$\text{Let h be the distance between the parallels}$

$\textsf{Now}$

$\textsf{Area of the parallelogram ABCD=Base * height=AB * h }$

$\textsf{Area of the parallelogram ABEF=Base * height=AB * h }$

$\implies\textsf{Area of the parallelogram ABCD=Area of the parallelogram ABEF}$

$\textsf{Hence proved}$