Question

A sphere of mass 50 x 10-kg moving with a velocity of 2 ms-
hits another sphere which is at rest. Assuming the collision to be
head-on collision and if they stick together after collision and
move in the same direction with a velocity of 0.5ms, find the
mass of the second sphere.​

Answer 1

Answer:

A body of mass 10 kg moving with a velocity of 5ms

−1

hits a body of 1 gm at rest. Find the velocity of the second body after collision assuming it to be perfectly elastic ?

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ANSWER

For a perfectly elastic collision, coefficient of restitution is e=1.

Let u and v be the velocities of 10 kg and 1 g masses after collision.

Thus, e=

rel. vel. of approach

rel. vel.of separation

=

5−0

v−u

=

5

v−u

But, as e=1, we have v−u=5.

Total momentum before collision is P=10×5=50 kg m/s

Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50

Thus, 10.001v−50=50⇒v=

10.001

100

≈10 m/s

Answered By

toppr

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