Physics, asked by pallosrivastava70277, 1 year ago

a sphere of mass M1 in motion hits directly another sphere of mass M2 at rest and sticks to it the total kinetic energy after collision is 2 by 3 of their total kinetic energy before collision find the ratio of M1:M2​

Answers

Answered by nagathegenius
0

Answer:

Explanation:

fractional loss in kinetic  energy

which is K BEFORE-K AFTER / K BEFORE

=M1M2/M1+M2(U1-U2)^2(1-E)

QUESTION SAYS THAT BALL STICK TO OTHER IN COLLISION THE IT IS INELASTIC COLLISION

FOR INELASTIC COLLISION E=0

THERFORE M1M2/M1+M2(U1-U2)=K-2K/3 /K

1/3

THEREFORE

M1M2/M1+M2(U1-U2)^2=1/3

M1+M2 (U1-U2)^2 =1/3

M1/M2=-(U1-U2)^2+1/3 /M2

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