Question

A sphere of radius 1 centimetre has a potential of 8000 fold the energy density near its surface will be

Answer 1

Answer:

Explanation:

density near its surface will be ......

(A) 64 × 105 (J/m3) (B) 2.83 (J/m3)

(C) 8 × 103 (J/m3) (D) 32 (J/m3)

Solution: Answer: (B) 2.83 (J/m3)

Energy density = (1/2)∈0E2

= (1/2) × 8.86 × 10–12 × (v/r)2

= 4.43 × 10–12 × [(8000) / (10–2)]2

= 283.5 × 10–2

= 2.83 J/m3