Math, asked by Sonalikulkarni9, 2 months ago

A sphere of radius 3 cm is melted and recast into a cylinder of height 9m. Find the radius of the cylinder. ​

Answers

Answered by kisti1145
1

hope it will be helpful to you

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Answered by shreya6475
2

radius of bigger sphere(R) = 3 cm

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cm

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = n

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger sphere

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³n = R³/r³

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³n = R³/r³n = (R³/r³)

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³n = R³/r³n = (R³/r³) n = (3/.03)³ = (10)³

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³n = R³/r³n = (R³/r³) n = (3/.03)³ = (10)³n = 1000

radius of bigger sphere(R) = 3 cmradius of smaller balls(r) = 0.6/2 = 0.3 cmlet the number of small balls = nn×volume of a small balls = volume of bigger spheren*4/3πr³ = 4/3πr³n = R³/r³n = (R³/r³) n = (3/.03)³ = (10)³n = 1000Number of small balls is 1000

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