A sphere of radius r carries a positive charge density (ρ) that increases linearly with radial distance r from the centre (ρ ∝ r). the radial dependence of the magnitude of electric field inside the sphere is given by
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Question Properly :
A sphere of Radius R carries a positive charge (p) that increases linearly with radial distance x
from the centre. Then,
Electric Field Intensity inside the sphere at a point 'r 'is proportional to :
---------------------
ELECTRIC FIELD DUE TO NON -UNIFORM VOLUME CHARGE DENSITY INSIDE THE SPHERE.
Final Answer : Electric Field is proportional to
where r is point where we have to find electric field.
Steps and Understanding :
1) We will make small spherical shells of thickness 'dx' at a distance 'x' from the centre .
2) Then, we will find Electric field due to these spherical shells at a distance 'r' from the centre .
3) Then, we get Spherical shells which are inside the spherical shell of radius' r ' will have Electric field
1/(4π£°) * dq/r^2 .
where dq is charge of small spherical shell.
4) And, Spherical shells which have radius
greater than 'r' have electric field 0 on that point 'r'.
5) So, We will integrate the dE according to our observation.
For Calculation see pic.
A sphere of Radius R carries a positive charge (p) that increases linearly with radial distance x
from the centre. Then,
Electric Field Intensity inside the sphere at a point 'r 'is proportional to :
---------------------
ELECTRIC FIELD DUE TO NON -UNIFORM VOLUME CHARGE DENSITY INSIDE THE SPHERE.
Final Answer : Electric Field is proportional to
where r is point where we have to find electric field.
Steps and Understanding :
1) We will make small spherical shells of thickness 'dx' at a distance 'x' from the centre .
2) Then, we will find Electric field due to these spherical shells at a distance 'r' from the centre .
3) Then, we get Spherical shells which are inside the spherical shell of radius' r ' will have Electric field
1/(4π£°) * dq/r^2 .
where dq is charge of small spherical shell.
4) And, Spherical shells which have radius
greater than 'r' have electric field 0 on that point 'r'.
5) So, We will integrate the dE according to our observation.
For Calculation see pic.
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