a sphere of radius r is melted and reshaped into a hollow cylinder of uniform thickness if the external radius of the base of the cylinder is 4 cm its height 24 cm and thickness 2 cm find the value of r
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Answered by
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r^3= 24*3/4(16-4)
r^3=18*12
r=6
r^3=18*12
r=6
aarrr:
can you explain on paper
give solution on paper
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Answered by
0
r^24*3/4(16-4)
r^3=18*12
r=6
r^3=18*12
r=6
please explain solution
on paper
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