a spheriacal ball is divided into two equal parts. if the cirved surface area of each half is 56.57cm square,find the volume of the spherical ball?
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4×pi×r^2=56.57cm^2
4×22/7×r^2=56.57
88/7×r^2=56.57
r^2=56.57×7/88
r^2=4.4998863636
r=2.121293559=2.12(app.)
now,total radius=2×2.12=4.24cm
volume=4/3×pi×r^3
=4/3×22/7×4.24^3
=88/21×76.225024
=248.437 cm^3 (approx)
4×22/7×r^2=56.57
88/7×r^2=56.57
r^2=56.57×7/88
r^2=4.4998863636
r=2.121293559=2.12(app.)
now,total radius=2×2.12=4.24cm
volume=4/3×pi×r^3
=4/3×22/7×4.24^3
=88/21×76.225024
=248.437 cm^3 (approx)
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