a spherical ball 28centimetre in diameter is melting and recast into a right circular conical mole the base of which is 35 cm in diameter find the height of correct to places of decimal
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1
Diameter = 28cm
Radius = 14cm
Volume of Sphere = 4/3πr³
= 4/3×22/7×14×14×14
= 11498.66cm³
Radius of ri8 circular cone = 17.5cm
Volume of Sphere = Volume of Cone
11498.66 = 1/3πr²h
1/3×22/7×17.5×17.5× h = 11498.66
h = 11498.66×7×22/22×17.5×17.5= 35.8
height after one place = 3.58
Radius = 14cm
Volume of Sphere = 4/3πr³
= 4/3×22/7×14×14×14
= 11498.66cm³
Radius of ri8 circular cone = 17.5cm
Volume of Sphere = Volume of Cone
11498.66 = 1/3πr²h
1/3×22/7×17.5×17.5× h = 11498.66
h = 11498.66×7×22/22×17.5×17.5= 35.8
height after one place = 3.58
Answered by
2
diameter of spherical ball = 28 cm
radius = 14 cm
therefore , its volume = 4/3 πr³
since , the spherical ball is melted and recasted into cone , hence,
there volume would be same
base diameter of cone = 35cm
radius = 35/2cm
therefore ,
volume of sphere = volume of cone
=> 4/3 π r³ = 1/3 π r² h
=> since , 3 from denominator and π cancels out
=> 4 × 14 × 14 × 14 = 35/2 × 35/2 × h
=> ( 4 × 14 × 14 × 14 × 2 × 2 ) / 35 × 35 = height
=> 43904 / 1225 = height
=> 35.84 cm = height of cone
hope this helps
radius = 14 cm
therefore , its volume = 4/3 πr³
since , the spherical ball is melted and recasted into cone , hence,
there volume would be same
base diameter of cone = 35cm
radius = 35/2cm
therefore ,
volume of sphere = volume of cone
=> 4/3 π r³ = 1/3 π r² h
=> since , 3 from denominator and π cancels out
=> 4 × 14 × 14 × 14 = 35/2 × 35/2 × h
=> ( 4 × 14 × 14 × 14 × 2 × 2 ) / 35 × 35 = height
=> 43904 / 1225 = height
=> 35.84 cm = height of cone
hope this helps
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