Question

A spherical ball of 1000 cm³ is subjected to a pressure of 10 atmosphere. The change in volume is 10⁻² cm³. If the ball is made of iron, find its bulk modulus. (1 atmosphere = 1 × 10⁵ N m⁻²).

Answer 1

Given, Volume of sphere, v = 1000cm³ = 1000 × 10^-6 m³ = 10^-3 m³

pressure , P = 10atm = 10 × 10^5 N/m²
= 10^6 N/m²

Change in volume of iron ball , ∆v = 10^-2 cm³ = 10^-2 × 10^-6 m² = 10^-8 m²

We know, bulk modulus, $\beta=\frac{P}{\frac{\Delta v}{v}}$

= 10^6/{10^-8/10^-3}

= 10^6 × 10^-3/10^-8

= 10¹¹ N/m²

Hence, bulk modulus = 1 × 10¹¹ N/m²

Answer 2

Explanation:

A spherical ball of 1000 cm³ is subjected to a pressure of 10 atmosphere. The change in volume is 10⁻² cm³. If the ball is made of iron, find its bulk modulus. (1 atmosphere = 1 × 10⁵ N m⁻²).