a spherical ball of lead 6 cm in radius is melted and recast into three spherical ball . the radii of two balls are 3 cm and 4 cm the radius of the third sphere is
Answers
Answered by
0
Answer:
5cm
Step-by-step explanation:
- 4/3*pi *216=4/3*pi*(27+64+x3)
- 216=91+x3
- x3=216-91
- x3=125
- x=cube root of 125
- x=5
- x is the third radius
Answered by
3
Answer:
radius = 5 cm
Step-by-step explanation:
Sphere ball small spheres
R = 6 cm r = 3 cm, r = 4cm , r = ?
Volume of three sphers = Volume of sphere
4/3 π (r³ + r³ + r³) = 4/3 π R³
4/3 π ( 3³ + 4³ + r³ ) = 4/3 x π x 6³
3³ + 4³ + r³ = 6³
27 + 64 + r³ = 216
r³ = 216 - 91
= 125
∴ r = 5 cm
the radius 0f the 3rd sphere = 5 cm
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