A spherical ball of radius 3 cm is melted and recast into three spherical balls.The radii of two of these balls are 1.5 cm and 2.5 cm.Find the radius of the third ball.
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➯ Radius = 2.5 cm
Full explanation:-
Given:
- Radius of spherical ball is 3 cm.
- Radii of new spherical balls are 1.5 cm and 2 cm.
To Find:
- Radius of third spherical ball ?
Solution :
- Let the radius of third spherical ball be x cm.
- If something is melted and recasted into another thing then their volumes will be equal. In short
- Volume of 1st thing = Volume of second one.
➯ Let's see here
- Volume of big spherical ball will be equal to the sum of volumes of that three small spherical balls.
As we know that
★ Volume of Sphere = 4/3πr³ ★
[ Taking big spherical ball ]
- Radius = 3 cm
- ⟹ Volume = 4/3 × π × (3)³
- ⟹ 4π/3 × 27
- Volume we got = 4π/3 × 27 cm³
[ Taking 3 small spherical balls ]
- Radius of first ball (r¹) = 1.5 cm
- For second (R) = 2 cm
- For third (x) = x cm
- Volume = 4/3 × π( sum cubes of radii)
- ⟹ Volume = 4/3 × π(1.5³ + 2³ + r³)
- ⟹ 4π/3 (3.375 + 8 + x³)
- ⟹ 4π/3 ( 11.375 + x³)
- Volume we got = 4π/3 (11.375 + x³) cm³
According to the question,
- First volume = Second volume
- ➮ 4π/3 × 27 = 4π/3 (11.375 + x³)
- ➮ 27 = 11.375 + x³
- ➮ 27 – 11.375 = x³
- ➮ 15.625 = x³
- ➮ 15625/1000 = x³
- ➮ 3125/200 = 625/40 = 125/8 = x³
- ➮ ³√125/8 = x³
- ➮ 5/2 = x²
- ➮ 2.5 cm = x
Hence, the measure of radius of third spherical ball is 2.5 cm.
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