A spherical balloon of 21 cm diameter is to be filled up with h2 at ntp
from a cylinder containing the gas at 20 atm 27°c. the cylinder can hold
2.82 litre of water at ntp. calculate the number of balloons that can be
filled up
Answers
HERE IS YOUR ANSWER,
⇔ Volume of balloon = 4.851 L (GIVEN)
NOW,
→ Let no. of balloon to be filled "n"
→ Total volume occupied by n balloons = 4.851 × n
Volume of H₂ present in cylinder = 2.82 L (GIVEN)
→ Total volume of H₂ at NTP = (4.851 × n + 2.82)L
SINCE,→ P₁ = 1 atm P₂ = 20 atm
→ V₁ = (4.85 × n) + 2.82 L
→ V₂ = 2.82 L
→ T₁ = 273 K
→ P₁V₁ / T₁ = P₂V₂ / T₂
→ 1 × (4.85 × n + 2.82) ÷ 273 = (20 × 2.82) ÷ 300
THEREFORE,
n = 48.504 / 4.851 = 10 balloons.
HOPE IT HELPS YOU,
THANK YOU. ^_^
A spherical balloon of 21 cm diameter is to be filled up with hydrogen at N.T.P. from a cylinder containing the gas at 20 atmospheres at 27oC. if the cylinder can hold 2.82 litres of water, calculate the number of balloons that can be filled up.
Answer:10
No. of balloons that can be filled = V of H2 available/V of one balloon
Calculation of total volume of hydrogen in the cylinder at N.T.P
P1V1/T1 = PV2/T2
P1 = 1 atm P2 = 20 atm
V1 = ? V2 = 2.82 l
T1 = 23 K T2 = 273 + 27 = 300 K
∴ V1 = 20 * 2.82 * 273/300 * 1 = 51.324 l = 51324 ml
Actual volume to be transferred into balloons
= 51324 – 2820 ml = 48504 ml
[∵ 2820 ml of H2 will remain in cylinder]
No. of balloons that can be filled up -= 48504/4851 = 9.999 = 10
Volume of one balloon = 4/3 πr3 = 4/3 * 22/7 * (21/2)3
[∵ r = diameter/2]
= 4851 ml = 4.851L