A spherical cavity of Radius R/2 is drilled in the centre of a plastic sphere of radius R and electric permittivity ε charged with a charge density ρ. Assuming the object sits in a vacuum and that the electric potential at infinity is zero, calculate the electric potential in the centre of the sphere.
Attachments:
Answers
Answered by
0
The electric potential in the centres of the sphere is E = Kq / (R/2) + Kq' / R
Explanation:
- The respective charges on the shell are q and q-
- The system is shown in the figure.
- Let x be the distance between the centres of the object.
Then for
X > R
Electrical potential is given as:
E = K(q + q ' ) / x
For R / 2 < x < R
Electric potential:
Kq / x + Kq' / R
For x < R/2 Electric potential = Kq / (R/2) + Kq' / R
Thus the electric potential in the centres of the sphere is E = Kq / (R/2) + Kq' / R.
Also learn more
In the given electric circuit if the current flowing through 3 ohm resistor in 2 A. Find the voltage of the battery and the current I drawn from it. ?
https://brainly.in/question/12560132
Similar questions
Math,
6 months ago
Biology,
6 months ago
Computer Science,
11 months ago
India Languages,
1 year ago