Physics, asked by thedarkgod007, 12 days ago

a spherical liquid drop has a diameter of 2 cm and is given a charge if 1uc​

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Answers

Answered by AbhayNarayanSingh
0

Answer:

Lets Give the charge on every little drop a chance to be q C.

In this way, VsmallVsmall=kqr→q=Vrk=kqr→q=Vrk

where VsmallVsmall is the potential on every little circle.

Add up to volume of every single little circle = Volume of vast drop

∴∴27×4/3πr3=4/3πR^327×4/3πr3=4/3πR^3

∴3r=R∴3r=R

∴Vlarge=kQ/R=k27q/3r=9Vsmall

Answered by stunithila2683
0

Answer:

Correct option is

A

9

If q be the charge on each drop, charge on big drop is Q=27q.

If R be the radius of bigger drop,

3

4

πR

3

=27(

3

4

πr

3

)⇒R=3r

Thus, V

1

=k

r

q

and V

2

=k

R

Q

=k

3r

27q

=9k

r

q

=9V

1

V

1

V

2

=9

Explanation:

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