a spherical liquid drop has a diameter of 2 cm and is given a charge if 1uc
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Answered by
0
Answer:
Lets Give the charge on every little drop a chance to be q C.
In this way, VsmallVsmall=kqr→q=Vrk=kqr→q=Vrk
where VsmallVsmall is the potential on every little circle.
Add up to volume of every single little circle = Volume of vast drop
∴∴27×4/3πr3=4/3πR^327×4/3πr3=4/3πR^3
∴3r=R∴3r=R
∴Vlarge=kQ/R=k27q/3r=9Vsmall
Answered by
0
Answer:
Correct option is
A
9
If q be the charge on each drop, charge on big drop is Q=27q.
If R be the radius of bigger drop,
3
4
πR
3
=27(
3
4
πr
3
)⇒R=3r
Thus, V
1
=k
r
q
and V
2
=k
R
Q
=k
3r
27q
=9k
r
q
=9V
1
∴
V
1
V
2
=9
Explanation:
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