Question

a spherical mirror produced an image of magnification -1 on a screen placed at a distance of 50cm from the mirror
1) which mirror is used?
2) Distance Of image from the object
3) the focal length of the mirror
4) conditions of a concave mirror can form an image larger than the actual object​

Answer 1

Answer:

$\huge\mathcal{\green{Hola!}}$

$\huge\mathfrak{\red{Answer}}$

• ➝ 1) concave mirror

• ➝ 2) Distance object,u = -50cm

• ➝ 3) Focal length, f = -25cm

• ➝ 4) Conditions : ➝ (object position) :

☞ Between C and F

☞At F

☞ Between P and F

Explanation:

☆ Question:-

A spherical mirror produced an image of magnification -1 on a screen placed at a distance of 50cm from the mirror, then find:

1) Which mirror is used?

2) Distance Of image from the object.

3) The focal length of the mirror.

4) Conditions of a concave mirror can form an image larger than the actual object.

☆ Required Solution:-

1) Type of mirror:

➜ Since, the magnification of the produced image is -1 therefore, the mirror involved is a concave mirror .

$\fbox{\purple{Mirror \ ↝ \ concave}}$

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2) The object distance, u :

➜ Image distance, v = -50cm

magnification, m = -1

$\huge\mathcal{\green{Now,}}$

$\huge m = - \frac{ v}{u}$

$= > - 1 = \frac{ -(- 50)}{u}$

$- u = 50 \: or \: u = -50cm$

$\huge\mathcal{\green{Therefore,}}$

Object Distance or distance of the image from the object is 50cm.

$\fbox{\purple{Object \ distance \ = \ -50cm}}$

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3) focal length, f :

• From the mirror formula we have,

$\huge \frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

Putting values we have,

$\frac{1}{-50} + \frac{1}{-50} = \frac{1}{f}$

$\frac{1}{f} = \frac{-2}{50}$

$f = \frac{-50}{2 } = -25cm$

$\fbox{\purple{focal \ length \ = \ -25cm}}$

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4) Conditions for a concave mirror to have an image produced larger than the actual object :

➜ When the object, for concave mirror, is placed at the following positions then we obtain an image that is larger in size than the actual object size:

⠀⠀⠀⠀⠀⠀⠀⠀⠀

Position of the object:

• Between Centre of curvature, C and Principal Focus, F of the mirror.

• At Principal Focus, F.

• Between the Pole, P and Principal Focus, F.

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$\huge\mathcal{\green{All \ the \ very \ best!}}$

$\huge\mathfrak{\red{@MissTranquil}}$

$\huge\fbox{\orange{be \ brainly}}$

Answer 2

Answer:

the above answer is correct go through it