A spherical portion has been removed from a solid sphere having a charge distributed uniformly in its volume as shown in the figure. The electric field inside the emptied space is
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assume in the cavity charge density p and -p.
let position of point from complete sphere is R vector and from cavity centre is r vector
net elec field= pR/3εo - pr/3εo = p(R-r)/3εo
= pa/3εo (from vector addition)
where a vector is from centre of sphere to centre of cavity. so we take any point inside the cavity elec field will be pa/3ε and it is independent of position of point in the cavity. hence uniform.
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let position of point from complete sphere is R vector and from cavity centre is r vector
net elec field= pR/3εo - pr/3εo = p(R-r)/3εo
= pa/3εo (from vector addition)
where a vector is from centre of sphere to centre of cavity. so we take any point inside the cavity elec field will be pa/3ε and it is independent of position of point in the cavity. hence uniform.
hope this is helpful to you
plz mark as brainliest plzzzzzzzz
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