A spherical steel ball bearing has a diameter of 2.540 cm at 25.00°C. a) What is its diameter when its temperature is raised to 100.0°C? b) What temperature change is required to increase its volume by 1.000%?
Answers
Answered by
5
Answer:
(a) The diameter is a linear dimension, so we consider the linear expansion of steel:
d=do [1+α(ΔT)]
=(2.540cm)[1+(11×10^-6(°C)^-1 (100.00°C−25.00°C)]
=2.542cm
(b) If the volume increases by 1%, then ΔV=(1.000×10^−2)Vo
. Then, using ΔV=ββVo (ΔT)
, whereβ=3α is the volume expansion coefficient, we find ΔT= (∆V/Vo)/B
=( 1.000 X 10^-2)/3[11.0×10^-6(°C)^-1]
=3 ×10² C
Explanation:
PLEASE----
MARK AS BRAINLIST ANSWER ❤️❤️
PLZZZ FOLLOW ME ❤️.
Similar questions