A spherical steel ball is melted to make a 8new identical balls find the ratio of the radius of the each new ball to radius of the original ball
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Answered by
75
Let the radius of the spherical steel ball be 'X'
Then the volume of the spherical steel ball=4/3πr³=4/3π(X)³
Let the radius of the small spherical balls be 'x'
Then, Volume=4/3π(x)³
According to question:-
4/3π(X)³=8[4/3πx³]
4/3(X)³=32/3x³
(X)³=8x³
X=2x
Therefore ratio- 1:2
Then the volume of the spherical steel ball=4/3πr³=4/3π(X)³
Let the radius of the small spherical balls be 'x'
Then, Volume=4/3π(x)³
According to question:-
4/3π(X)³=8[4/3πx³]
4/3(X)³=32/3x³
(X)³=8x³
X=2x
Therefore ratio- 1:2
kvnmurty:
ratio asked is 1:2..
Answered by
57
let the radius of original ball be : R
let the radius of new ball be r.
Volume of the original ball is equal to the total volume of 8 new balls.
4/3 * π R³ = 8 * 4/3 * π r³
=> R = 2 r
=> Ratio: r : R = 1 : 2
let the radius of new ball be r.
Volume of the original ball is equal to the total volume of 8 new balls.
4/3 * π R³ = 8 * 4/3 * π r³
=> R = 2 r
=> Ratio: r : R = 1 : 2
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