Question

A Sponge scrubber soaked in water weighs 100 g. The wet scrubber has 99% water in it. If it is dried in the sun to reduce the water to 98%. How much will it weigh (in g) now?​

Answer 1

Given data:

• A spong scrubber soaked in water weighs 100 g, where the scrubber has 99% water in it.

• It is dried in the sun to reduce the water to 98%.

To find:

The weight of the scrubber when water is reduced to 98%

Step-by-step explanation:

Given, the scrubber soaked in water weighs 100 g, where the scrubber has 99% water in it.

Then the weight of the water in it

= 100 × 99/100 g

= 99 g

and the weight of the dry scrubber is (100 - 99) g = 1 g.

The wet scrubber is dried in the sun to reduce the water to 98%.

Let, x be the weight of the wet scrubber when the water is 98%. Then we form a relation:

98% of x g + weight of the dry scrubber = x g

⇒ 98x/100 + 1 = x

⇒ x - 98x/100 = 1

⇒ (100x - 98x)/100 = 1

⇒ 2x/100 = 1

⇒ 2x = 100

⇒ x = 50

Final Answer:

It will weigh 50 g now.

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A sponge scrubber soaked in water weighs 100 g. The wet scrubber has 99% water in it. If it is dried in the sun to reduce ...

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