factorize by using factor theorem :x^3 - 5x + 4
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Answer:
Step-by-step explanation:
Given
f(x)=x
3
+2x
2
−5x−6
To find a factor of f(x) we assume different values of x and substitute it in f(x)
First we consider the factors of the constant term −6 i.e., ±1,±2,±3,±6
Now we substitute the values of x in f(x)
If f(x)=0 for some value a
Then (x−a) is a factor of f(x)
[Note : This is a hit and trial method, So you have to iterate the process until you get the required x]
Substituting x=−1 in f(x) , We get,
f(−1)=(−1)
3
+2(−1)
2
−5(−1)−6
=−1+2(1)+5−6
=−1+2+5−6
=−7+7
=0
∴ By factor theorem,
(x+1) is a factor of f(x)
Now dividing f(x) by (x+1), we get
x
3
+2x
2
−5x−6
=(x+1)(x
2
+3x−2x−6)
=(x+1){x(x+3)−2(x+3)}
=(x+1)(x−2)(x+3)
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