Question

a spring 60 cm long is stretched by 2 cm by the application of a load of 200g. what will be the length when a load of 500 g is applied​

Answer 1

✪ᴀɴsᴡᴇʀ✪

• On applying 500 gram, length of the spring will be 65 cm.

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

☆ɢɪᴠᴇɴ☆

• A spring 60 cm long stretched by 2 cm when 200 gram load is applied.

☆ᴛᴏ ғɪɴᴅ☆

• Length of spring when 500 gram load is applied.

☆ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ☆

Here,

$\to l_0 = 60\:cm$

$\to F_1 = 0.2g = 1.96N, x_1 = 2\: cm$

$\to F_2 = 0.5g = 4.9N$

Force and displacement in a spring are related as

$\to F = kx$

$\to 1.98N = k\times 2\: cm$

$\to \boxed{ k = 0.98\:N/cm}$

Applying this equation in the second case,

$\to 4.9N = (0.98\:N/cm)\times x_2$

$\to x_2 =\frac{4.9N}{0.98\:N/cm}$

$\to \boxed{x_2 = 5\:cm}$

Therefore, lotal length of the spring,

$\to l = l_0 + x_2$

$\to l = 60 + 5$

$\to \boxed{l = 65\:cm}$

Answer 2

Answer:

The total length of the spring becomes 65 cm.

Explanation:

kx = mg

k = mg/x

k = 0.2×10/0.02

k=100

100 x = 0.5×10

x = 5cm

So the total length is 60 + 5 = 65 cms