A spring balance is attached to 2 kg trolley and is used to pull the trolly along a flat surface as shown in the fig. The reading on the spring balance remains at 10 kg during the motion. The acceleration of the trolly is
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Answered by
70
The reading on the spring balance = m
so the tension force applied = mg
In the above case
m₁a = mg
m₁ is the mass of the trolley and m is the Reading on the spring balance;
2*a = 10*9.8
⇒ a = 49 m/s²
Answer the acceleration of the trolley is 49 m/s²
so the tension force applied = mg
In the above case
m₁a = mg
m₁ is the mass of the trolley and m is the Reading on the spring balance;
2*a = 10*9.8
⇒ a = 49 m/s²
Answer the acceleration of the trolley is 49 m/s²
Answered by
43
Let a be the acceleration of the trolley we have to find.
2 x a = 10 x 9.8
a = 49 m/s²
The acceleration of the trolley is 49 m/s²
2 x a = 10 x 9.8
a = 49 m/s²
The acceleration of the trolley is 49 m/s²
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