Question

A spring has an extension of 20 cm . Calculate the elastic potential energy stored in the spring if it has a spring constant of 100N / m .​

Answer 1

Answer:

Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension to work out the extension do

100Nm

−

1

20N

=0.2m.

now we have our variables put them into the formula

(

2

1

)×100Nm

−1

×0.2m

2

=2J while it is a form of energy so the units are obviously Joules we can work it out that they are Joules our units in the equation are Nm^-1 * m^2 which simplifies to Nm which using the formula Work = Force * Distance and given Work has unit Joules then Newtons*Metres = Joules

Answer 2

Answer:

.2

Explanation:

EPE= 1/2kx^2

EPE= (1/2)(100)(.02^2)

since its in cm you have to convert to meters 20 cm = 0.02 m

EPE= .2