Question

A spring, having a spring constant of 350 kn/m , is initially compressed by 0.4 cm . The work required ( in j ) to compress it by another 0.6 cm (up to 1 decimal place) is

Answer 1

Answer:0.0126j

Explanation:spring force=kx

Workdone equals to f*s

S displacement

Where x is displacement in metres

And k is spring constant

First the spring was compressed by

0.4cm i.e 0.004m

Workdone = 0.004×350×0.004

=5.6×10^-3

Again spring was compressed by 0.006m

Workdone =0.006×350×0.006

=0.0126

Answer 2

The amount of work required the spring is 0.0042 joule

Explanation:

Given Data

Spring constant value (K) = 350 k-N/m

initial compression of the spring = 0.4 cm =0.004 m

Final compression of the spring = 0.6 cm = 0.006 m

To find the work required to compress the spring up to 0.006 m

Force required to compress the spring is equal to the product of spring constant value and the distance traveled by the spring.

Force = spring constant × Distance traveled by the spring

Force =  350× 0.004

Force = 1.4 k-N

Work required to compress the spring is equal to half the product of spring constant and square of the displacement.

$\text {workdone} = \frac{1}{2} \times K \times x^{2}$

Also, $\text { Workdone} = \frac{1}{2} \times F \times x$

$\text { Workdone} = \frac{1}{2} \times 1.4 \times 0.006$

Workdone = 0.0042 kN-m

one kilo Newton meter = one joule

Workdone = 0.0042 joule

Therefore the amount of work required to compress the spring by another 0.6 cm is 0.0042 joule

To Learn More ...

https://brainly.in/question/6693856

https://brainly.in/question/1525486