Physics, asked by yashbanna21, 9 months ago

A spring is characterized by a spring constant of 60 N/m. How much potential energy does it store, when
stretched by 1.0 cm?
(A) 3.0 x10-'J (B) 0.30J
(C) 60 J
(D) 600 J​

Answers

Answered by Anonymous
41

\huge\underline{\underline{\bf \orange{Question-}}}

A spring is characterized by a spring constant of 60 N/m. How much potential energy does it store, when streched by 1 cm.

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Spring Constant (k) = 60 N/m
  • It's streched by (x) = 1 cm ➝ 0.01m

\large\underline{\underline{\sf To\:Find:}}

  • Potential Energy ( U )

\large\underline{\underline{\sf Formula\:Used:}}

\large{\boxed{\bf \blue{Potential\: Energy (U)=\dfrac{1}{2}kx^2} }}

\implies{\sf U = \dfrac{1}{2}×60×(0.01)^2 }

\implies{\sf  U = \dfrac{1}{2}×60×1×10^{-4}}

\implies{\sf U = 30 × 10^{-4} }

\implies{\bf \red{Potential\: Energy ( U) = 3 × 10^{-3}J} }

\huge\underline{\underline{\bf \orange{Answer-}}}

Potential energy it store, when stretched by 1.0cm is {\bf \red{3×10^{-3}J}}.

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