Question

A spring is placed horizontally on a frictionless table. The spring constant of the spring is 50 N/m, and it is compressed 0.1 m by a 2 kg block. a. How much energy is stored in the spring

Answer 1

Explanation:

this is a simple question it's a direct formula you need to apply the potential energy of the spring which is equal to half into ke x square

Answer 2

Answer:

A spring is placed horizontally. The spring constant of the spring is 50 N/m, and it is compressed 0.1 m by a 2 kg block, the energy is stored in the spring $0.25Nm$

Explanation:

• The elastic potential energy stored in the spring of spring constant (K) when displaced to a distance (x) is    

         $U=\frac{1}{2}kx^{2}$

From the question, we have

the spring constant of the spring $K=50N/m$

compressed length $x=0.1m$

put the given values

⇒

the energy stored is

$U=\frac{1}{2}*50*0.1^{2}$

⇒$U=0.25Nm$