Question

A spring is pulled to 10 cm and held in place with a force of 500n. what is the spring constant of a spring

Answer 1

Explanation:

The change in position is 10 cm. Since the units on the spring constant are Newtons per meter, we need to change the distance to meters.

Δx = 10 cm = 0.10 m

F = k·Δx

Solve this for k by dividing both sides by Δx

F/Δx = k

Since the force is 500 N, we get

500 N / 0.10 m = k

k = 5000 N/m

Answer: The spring constant of this spring is 5000 N/m.