Physics, asked by NayyarSultana, 1 year ago

A spring is stretched 10 cm. The work done is K kj. The extra eork done to stretch the spring 10 cm more is ​

Answers

Answered by TheChampion
3

work done 0.5k( y² - x² )

using this 0.5k(0.1²) = K

extra work =0.5k(0.2² - 0.1²) = 3K


NayyarSultana: Thnx a lot...
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