Question

plzz help me out. I am confused . a t this question ​

Answer 1

in quad .ABCD

angle ( A + B + C + D ) = 360 degree

ANGLE ( C + D ) = 360 degree - ANGEL ( A +B )

ANGLE C + D /2 = 360/2 - ang.(A + B )/2

ang. (DCO + CDO ) = 180 degree - ang. ( A + B )/2 ........ (i)

IN TRIANGLE COD

ang.(COD + DCO + CDO ) = 180 degree

angle COD + 180 degree - ang. (A + B )/2=180 degree

angle COD - ang. (A+ B )/2 = 0

ANGLE COD = 1/2 (A + B )