A spring is stretched 5 10 m
−2
× by a force of .N 5 10−4
× A mass of 0.01 kg is placed
on the lower end of the spring. After equilibrium has been reached, the upper end of the
spring is moved up and down so that the external force acting on the mass is given by
F(t) = 20 cos ωt. Calculate (i) the position of the mass at any time, measured form the
equilibrium position and (ii) the angular frequency for which resonance occurs.
Answers
Answered by
1
Answer:
ooo teri kya hai bhai ye
Similar questions