Math, asked by Zaki07786, 1 year ago

A spring is stretched 5 10 m

−2

× by a force of .N 5 10−4

× A mass of 0.01 kg is placed

on the lower end of the spring. After equilibrium has been reached, the upper end of the

spring is moved up and down so that the external force acting on the mass is given by

F(t) = 20 cos ωt. Calculate (i) the position of the mass at any time, measured form the

equilibrium position and (ii) the angular frequency for which resonance occurs.​

Answers

Answered by rishabh7346
1

Answer:

ooo teri kya hai bhai ye

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