Physics, asked by vidhyavarshan3180, 6 months ago

A spring of force constant 10 N/m has an initial stretch 0.20 m. in changing the stretch to 0.25 m, increase in potential energy is about

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Answered by Ayushmita09
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A spring of Force constant 10 N/m has an initial stretch 0.20m.In changing the stretch to 0.25 m,the increase in potential energy is about(CPMT 1977)A)0.1 joule

Answered by TheQuantumMan
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