A spring of force constant 800N/m has an extension of 5 cm. The work done in extending it from 5cm to 15cm is
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The work done is stored as elastic potential energy in the spring.
It is given by
W = 1/2 × k ( x₂² - x₁²)
x₁ = 5 cm
x₂ = 15 cm
Force constant, k = 800 N/m = 800/100 N/cm = 8 N/cm
W = 1/2 × 8 ( 15² - 5²) = 1/2 × 8 ( 225 - 25) =
= 1/2 × 8 × 200 = 800 N cm
W = 800 N cm = 8 N m = 8 J
Therefore,
The work done in extending it from 5cm to 15cm is 8 J.I hope it helps you ^_^
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