Question

A spring of force constant 800N/m has an extension of 5cm . The work done in extending it from 5cm to 15cm is [AIEEE 2002] ​

Answer 1

Answer:

$\boxed{Your\;Answer\; is \; 8J}$

Explanation:

W=1/2​×k(x₂²−x₁²)

Let the extensions be x1 and x2

x1=5cm

x2=15cm.

K = 800 N/m​=800N/100​cm=8N/cm

W=1/2×8(15²−5²)= 1/2​×8(225−25)

=1/2​×8×200 =800N/cm

W=800N/cm=8N/m​ = 8J.

Answer 2

Explanation:

Your Answer is 8J

$\boxed{W=1/2×k(x₂²−x₁²)}$

Let the extensions be x1 and x2

x1=5cm

x2=15cm.

K = 800 N/m=800N/100cm=8N/cm

W=1/2×8(15²−5²)= 1/2×8(225−25)

=1/2×8×200 =800N/cm

W=800N/cm

=8N/m

= 8J.