A spring of force constant 800N/m has an extension of 5cm.the work done in extending it from 5cm to 15 CM is
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Work done by the spring=k[(r1)^2-(r2)^2]÷2
r1=10cm r2=0cm (since it is already extended 5cm)
therefore W=800(0.0100-0)÷2
=4J
r1=10cm r2=0cm (since it is already extended 5cm)
therefore W=800(0.0100-0)÷2
=4J
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