Question

A spring of natural length L compressed to length 7L/8 exerts a force F. The work done by the spring in restoring itself to natural length is.. 1. FL/25 2.FL/16 3.3FL/25 4.FL/8

Answer 1

Natural length of spring =L.
Spring compressed to 7L/8.
hence spring compressed by=L-(7L/8)
=L/8.
further suppose spring constant is 'k'
then,
k(L/8)=F..........(Given)
=> k(spring constant)=8F/L...........(1)
Work done (W) by the spring in restoring its natural length is given by:
W= (1/2)×k×(L/8)×(L/8)............(2)
putting value of 'k' in equation (2) . we get the desired result.
ie. W=FL/16

Answer 2

Answer:

Explanation:

Natural length of spring =L.

Spring compressed to 7L/8.

hence spring compressed by=L-(7L/8)

=L/8.

further suppose spring constant is 'k'

then,

k(L/8)=F..........(Given)

=> k(spring constant)=8F/L...........(1)

Work done (W) by the spring in restoring its natural length is given by:

W= (1/2)×k×(L/8)×(L/8)............(2)

putting value of 'k' in equation (2) . we get the desired result.

ie. W=FL/16

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