Question

a spring of spring constant 100Nm-1 then then the minimum work done in joule in increasing the extension from5cm to 15cm​

Answer 1

Answer:

Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension to work out the extension do

100Nm

−

1

20N

=0.2m.

now we have our variables put them into the formula

(

2

1

)×100Nm

−1

×0.2m

2

=2J while it is a form of energy so the units are obviously Joules we can work it out that they are Joules our units in the equation are Nm^-1 * m^2 which simplifies to Nm which using the formula Work = Force * Distance and given Work has unit Joules then Newtons*Metres = Joules

Explanation:

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