Question

A sprinkler is deployed to irrigate garden . The speed of water jet from the sprinkler is u. The maximum area which can be irrigated by the sprinkler is

Answer 1

Answer: π (v^2/g)^2

Explanation:

The question is from projectile motion....

For maximum area, you will require the water to cover maximum distance. ( Note that the sprinkler is going to sprinkle the water in circular area.)

Now to have maximum area , you need maximum radius, say R.

For R to be maximum, the water should be projected at 45° w.r.t. horizontal.

R= v^2/g.... sin2theta= 1

.: Maximum area =πR^2.

A = π ( v^2/g) ^2.