Math, asked by shalakhaasingh, 5 months ago

a square + 1/a square=23 find a+1/a​

Answers

Answered by tamoghno62
0

Answer:

a^2+1/a^2=23

a^2+1/a^2-25=0

a^4+1-25a^2/a^2=0

a^4-25a^2+1=0

(a^2+5a)(a^2-5a)=-1

Therefore

a^2+5a=-1

a^2+5a+1=0

or

a^2-5a=-1

a^2-5a+1=0

solve further to get answer

Answered by utkarshpr
1

Answer:

±5

Step-by-step explanation:

Solution is in the image...

hope this helps!

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