a square + 18 A + 65 by using splitting middle term
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Hey Buddy !☺
![let \: p(x) = {a}^{2} + 18a + 65 \\ \\ \therefore \: \: \: p(x) = {a}^{2} + 18a + 65 \\ = {a}^{2} + 13a + 5a + 65 \\ = {a}(a + 13) + 5(a + 13) \\ = (a + 5)(a + 13) \\ \\ = > p(x) = (a + 5)(a + 13) \\ \\ now \: put \: p(x) = 0 \\ \\ \therefore \: (a + 5)( a+ 13) = 0 \\ = > (a + 5) = 0 \: \: \: or \: \: \: (a + 13) = 0 \\ = > \fbox{a = - 5 \: \: \: or \: \: \: a = - 13} let \: p(x) = {a}^{2} + 18a + 65 \\ \\ \therefore \: \: \: p(x) = {a}^{2} + 18a + 65 \\ = {a}^{2} + 13a + 5a + 65 \\ = {a}(a + 13) + 5(a + 13) \\ = (a + 5)(a + 13) \\ \\ = > p(x) = (a + 5)(a + 13) \\ \\ now \: put \: p(x) = 0 \\ \\ \therefore \: (a + 5)( a+ 13) = 0 \\ = > (a + 5) = 0 \: \: \: or \: \: \: (a + 13) = 0 \\ = > \fbox{a = - 5 \: \: \: or \: \: \: a = - 13}](https://tex.z-dn.net/?f=let+%5C%3A+p%28x%29+%3D++%7Ba%7D%5E%7B2%7D+%2B+18a+%2B+65+++%5C%5C++%5C%5C++%5Ctherefore++%5C%3A++%5C%3A++%5C%3A+p%28x%29+%3D+++%7Ba%7D%5E%7B2%7D++%2B+18a+%2B++65+%5C%5C++%3D++%7Ba%7D%5E%7B2%7D++%2B+13a+%2B+5a+%2B+65+%5C%5C++%3D++%7Ba%7D%28a+%2B+13%29+%2B+5%28a+%2B+13%29+%5C%5C++%3D+%28a+%2B+5%29%28a+%2B+13%29+%5C%5C+++%5C%5C+%3D++%26gt%3B+p%28x%29+%3D+%28a+%2B+5%29%28a+%2B+13%29+%5C%5C++%5C%5C+now+%5C%3A+put+%5C%3A+p%28x%29+%3D+0+%5C%5C++%5C%5C++%5Ctherefore+%5C%3A+%28a+%2B+5%29%28+a%2B+13%29+%3D+0+%5C%5C++%3D++%26gt%3B+%28a+%2B+5%29+%3D+0+%5C%3A++%5C%3A++%5C%3A+or+%5C%3A++%5C%3A++%5C%3A+%28a+%2B+13%29+%3D+0+%5C%5C++%3D++%26gt%3B++%5Cfbox%7Ba+%3D++-+5+%5C%3A++%5C%3A++%5C%3A+or+%5C%3A++%5C%3A++%5C%3A+a+%3D++-+13%7D)
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