Question

a square+6a+5 by a+1.

Answer 1

Here's your answer Mate!!

a(1)= 1 +6+5

a(1)=12....

Or some other way we have ...

${a }^{2} + 6a + 5 \\ {a}^{2} +5a + 1a + 5 \\ a(a + 5) + 1(a + 5) \\ (a + 1)(a + 5)$
Hope it Helps!!

Answer 2

a²+6a +5 ÷ a+1
a²+6a +5
5 x 1=5
5 + 1=6
a²+5a+1a +5
Now group them;
(a²+5a)+(1a +5)
Now take the common out;
a(a+5)+1(a+5)
(a+1)(a+5)÷(a+1)
now the (a+1) and (a+1) will cancel and the answer will be;
(a+5)
If you are finding the value of a;
a=-5
I hope it helps u !!!!!