Question

find the value of k for which 4y=kx- 10 and
$3y = 2y + 5$

have infinitely many solution

Answer 1

4y=kx-10
4y-kx+10=0
ax+by+c=0

let put the value of x be 1 and y be 2

4y-kx+10=0
4×2-k×1+10=0
8-k=-10
-k=-10/8
-k=-4/5
k=4/5

like this we put any value of x and y and have many solution


hope this help you...
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