Question

A square A is reduced to square B during this reformation the area reduced is

Answer 1

I set the side length of a square is 1 ( just to simplify the calculation). Set x = p/100 ( since p is in percent, for instance, p = 50% , x = 0.5) Area = 1^2 = 1

New side length = 1*( 1-x) = 1-x , Area after the reduction = (1-x)^2

the resulting percent reduction = (1- (1-x)^2)/1 *100% = [1- ( 1- 2x+ x^2)] * 100% =( 2x - x^2 ) *100%

MERRY CHRISTMAS