Question

A square and a rectangle each have a perimeter of 40 m. The difference between areas of
the two figures is 9m². What are the possible dimensions of the rectangle?​

Answer 1

Answer:

PS=PR

PS=PRPS=40+40+40+40=160cm

PS=PRPS=40+40+40+40=160cmPR=2(l)+(b)2=2(l+b)=2(10+b)cm

PS=PRPS=40+40+40+40=160cmPR=2(l)+(b)2=2(l+b)=2(10+b)cm∴160=2(10+b)

PS=PRPS=40+40+40+40=160cmPR=2(l)+(b)2=2(l+b)=2(10+b)cm∴160=2(10+b)⇒80=10+b

PS=PRPS=40+40+40+40=160cmPR=2(l)+(b)2=2(l+b)=2(10+b)cm∴160=2(10+b)⇒80=10+b⇒b=70cm

HOPE YOU GOT YOUR ANSWER.