Question

a square and a rectangle have equal perimeters. the length of a side of the square is 4x-1. The length of the rectangle is 2x+2 and the width is 2x. Write and solve an equation to find x.

Answer 1

Square Perimeter = 4(4x-1)

Rectangle Perimeter = 2(2x+1) + 2(x+2)

Square Perimeter = Rectangle Perimeter

4(4x-1) = 2(2x+1) + 2(x+2)

16x - 4 = 4x + 2 + 2x + 4

16x - 4 = 6x + 6

-6x  +4  -6x  +4

10x = 10

x = 1

Hope this helps and good luck my friend.

Answer 2

Answer:

x=1

Step-by-step explanation:

perimeter of square=4×side

=4(4x-1)

=16x-4 ----(eqn1)

perimeter of rectangle=2(l+b)

=2(2x+2+2x)

=8x+4 --(eqn2)

from equation 1 and 2

perimeter of square=perimeter of rectangle

I.e. 16x-4=8x+4

16x-8x=4+4

8x=8

x=8/8

x=1

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