Probability of obtaining genotype AABbcc in cross between AaBbCc ^ AaBbcc is (1)1/16
(2)1/8
(3)1/32
(4)1/64
Plz give the formula and explanation
Answers
Answered by
1
Answer:
The correct answer is the last choice, 1/64
Explanation:
The probability of producing the homozygote AABBCC is 1/64, assuming that Mendel's law of segregation is true. The probability of generating a homozygote recessive individual of genotype aabbcc is also 1/64.
The probability of producing the homozygote AABBCC is 1/64, assuming that Mendel's law of segregation is true. The probability of generating a homozygote recessive individual of genotype aabbcc is also 1/64.hope its correct ..
Answered by
1
Answer:
1/64 is the correct answer
hope it will help you
Similar questions