a square and a rectangle have the same perimeter the dimension of rectangle field are 120*90 find which has greater area
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here perimeter of the rectangle =>2(120+90)
=> 2*210=>420
therefore perimeter of square => 420
=> 4s=>420. => s=>420/4. =>105
now area of rectangle=> 120*90=>10800
area of square => 105*105=>11025
therefore the area of square is more
=> 2*210=>420
therefore perimeter of square => 420
=> 4s=>420. => s=>420/4. =>105
now area of rectangle=> 120*90=>10800
area of square => 105*105=>11025
therefore the area of square is more
Answered by
1
Length of rectangle field= 120
Breath of rectangle field= 90
Perimeter of rectangle= 2(l+b)
=2(120+90)
=2(210)
=420
Perimeter of Square= side×4
420= side×4
side= 420/4
side= 105
Area of square= (side)^2
=(105)^2
=11025
Area of rectangular field= l×b
=120*90
=10800
Therefore the area of the square is greater than the area of the rectangular field.
Hope this helps!
Breath of rectangle field= 90
Perimeter of rectangle= 2(l+b)
=2(120+90)
=2(210)
=420
Perimeter of Square= side×4
420= side×4
side= 420/4
side= 105
Area of square= (side)^2
=(105)^2
=11025
Area of rectangular field= l×b
=120*90
=10800
Therefore the area of the square is greater than the area of the rectangular field.
Hope this helps!
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