A square and a rectangular field with measurements of a given in the figure have the same perimeter. Find the of the given figure.
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Let the side of square field be a=60 m
Let the length of the rectangular field be l=80 m and breadth be b m.
According to the question
perimeter of square = Perimeter of rectangle
4×a=2(l+b)
⇒4×60=2(80+b)
⇒240=160+2b
⇒2b=80
⇒b=40
Area of square =60×60=3600m
2
Area of rectangle=80×40=3200m
2
So, the area of the square is greater than t
So, the area of the square is greater than the area of the rectangle.
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