Math, asked by sandeepkumar7874, 1 year ago

a square and an equiltral triangle have equal perimeters if the diagonal of the square is 6 root 2 cm then find the area of the triangle​

Answers

Answered by rijjuramesh2012
0

Answer:

Step-by-step explanation:

Hope it helps u Sandeep Kumar.. ..

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Answered by nagathegenius
0

Answer:

Step-by-step explanation:

perimeter of square =perimeter of equalateral triangle

4a=3x

given

diagonal of square

=6root2=sideroot2

side=6

from first written equation

4*6=3x

24=3x

x=8

area of triangle=1/2*base*height

as it is equalateral triangle if we take perpendicular bisector of base

it becomes two right angled triangles

hypotenuse^2= (side)^2+side^2

side=sqrt(hypotenuse^2-side^2)

side=sqrt(9-2.25)

=2.6

area=1/2base*height

1/2*3*2.6=1.5*2.6=3.9cm^2~4cm^2

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