(a square - b square) (c square - d square) - 4abcd
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hayy mate here your answer ✔️ ✔️
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Solution:-
(a^2-b^2)(c^2-d^2)-4abcd
a²c²-a²d²-b²c²+b²d²-4abcd
a²c²-a²d²-b²c²+b²d²-2abcd-2abcd
a²c²+b²d²-2abcd-a²d²-b²c²-2abcd
(a²c²+b²d²-2abcd)-(a²d²+b²c²+2abcd)
[(ac)²+(bd)²-2abcd]-[(ad)²+(bc)²+2abcd]
We know that,
[x²+y²-2xy=(x-y)²] and
[x²+y²+2xy=(x+y)²]
=>(ac−bd)²−(ad+bc)²
We know that,
[(a²-b²)=(a+b)(a-b)]
=>[ac-bd+(ad+bc)][ac−bd)−(ad+bc)]
=>(ac-bd+ad+ac)(ac-bd-ad-bc) ANSWER...
______________________________
❤️⭐I hope you mark as brainlist answer⭐❤️✨✨✨
_____________________________
Solution:-
(a^2-b^2)(c^2-d^2)-4abcd
a²c²-a²d²-b²c²+b²d²-4abcd
a²c²-a²d²-b²c²+b²d²-2abcd-2abcd
a²c²+b²d²-2abcd-a²d²-b²c²-2abcd
(a²c²+b²d²-2abcd)-(a²d²+b²c²+2abcd)
[(ac)²+(bd)²-2abcd]-[(ad)²+(bc)²+2abcd]
We know that,
[x²+y²-2xy=(x-y)²] and
[x²+y²+2xy=(x+y)²]
=>(ac−bd)²−(ad+bc)²
We know that,
[(a²-b²)=(a+b)(a-b)]
=>[ac-bd+(ad+bc)][ac−bd)−(ad+bc)]
=>(ac-bd+ad+ac)(ac-bd-ad-bc) ANSWER...
______________________________
❤️⭐I hope you mark as brainlist answer⭐❤️✨✨✨
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